C++ if Wrong Input How Ask Again
How to make this programme ask for input again if invalid input is entered (in C programming)? [indistinguishable]
https://stackoverflow.com/questions/42464437/how-to-make-this-program-ask-for-input-again-if-invalid-input-is-entered-in-c-p?fbclid=IwAR1BB7wkcELX0D_GkWAOVPe7m3of-gWMo60PztXTV1YqFD6jijQy1oYkR70
Loop Infinite
#include <stdio.h> #include <ctype.h> int chief ( void ) { char ch ; float num1 , num2 , answer ; printf ( "Enter the functioning of your choice:\n" ); printf ( "a. add s. decrease\northward" ); printf ( "g. multiply q. split\n" ); printf ( "q. quit\n" ); while (( ch = getchar ())!= 'q' ) { ch = tolower ( ch ); //Ignore whitespace if ( ch == '\n' ) proceed ; else { switch ( ch ) { //Improver part case 'a' : //First number printf ( "Enter showtime number: " ); //Check to see if input is a number while ( scanf ( "%f" ,& num1 )== 0 ) { printf ( "Invalid input. Please enter a number, such as 2.5, -1.78E8, or three: " ); scanf ( "%*s" ); } //2d number printf ( "Enter second number: " ); while ( scanf ( "%f" ,& num2 )== 0 ) { printf ( "Invalid input. Please enter a number, such as 2.v, -1.78E8, or 3: " ); scanf ( "%*due south" ); } //Do math for respective functioning reply = num1 + num2 ; //Impress out upshot printf ( "%.3f + %.3f = %.3f\n" , num1 , num2 , answer ); break ; //Subtraction function instance 's' : printf ( "Enter beginning number: " ); while ( scanf ( "%f" ,& num1 )== 0 ) { printf ( "Invalid input. Delight enter a number, such every bit 2.5, -i.78E8, or 3: " ); scanf ( "%*s" ); } printf ( "Enter 2nd number: " ); while ( scanf ( "%f" ,& num2 )== 0 ) { printf ( "Invalid input. Delight enter a number, such equally 2.five, -one.78E8, or 3: " ); scanf ( "%*s" ); } reply = num1 - num2 ; printf ( "%.3f - %.3f = %.3f\n" , num1 , num2 , answer ); interruption ; //Multiplication office case 'm' : printf ( "Enter beginning number: " ); while ( scanf ( "%f" ,& num1 )== 0 ) { printf ( "Invalid input. Please enter a number, such as ii.5, -i.78E8, or 3: " ); scanf ( "%*s" ); } printf ( "Enter second number: " ); while ( scanf ( "%f" ,& num2 )== 0 ) { printf ( "Invalid input. Please enter a number, such as 2.5, -1.78E8, or 3: " ); scanf ( "%*due south" ); } reply = num1 * num2 ; printf ( "%.3f * %.3f = %.3f\northward" , num1 , num2 , answer ); interruption ; //Division part example 'd' : printf ( "Enter starting time number: " ); while ( scanf ( "%f" ,& num1 )== 0 ) { printf ( "Invalid input. Please enter a number, such as two.5, -1.78E8, or 3: " ); scanf ( "%*s" ); } printf ( "Enter second number: " ); while ( scanf ( "%f" ,& num2 )== 0 ) { printf ( "Invalid input. Please enter a number, such equally 2.v, -ane.78E8, or 3: " ); scanf ( "%*s" ); } //Check for if number is a zilch while ( num2 == 0 ) { printf ( "Please enter a non-zero number, such equally 2.5, -1.78E8, or iii: " ); while ( scanf ( "%f" ,& num2 )== 0 ) { printf ( "Invalid input. Please enter a number, such as 2.5, -1.78E8, or 3: " ); scanf ( "%*s" ); } } respond = num1 / num2 ; printf ( "%.3f / %.3f = %.3f\n" , num1 , num2 , answer ); break ; //For if a not-valid performance is entered default : printf ( "That is not a valid operation.\north" ); suspension ; } } printf ( "Enter the functioning of your choice:\n" ); printf ( "a. add s. decrease\n" ); printf ( "m. multiply q. divide\north" ); printf ( "q. quit\north" ); } printf ( "Adieu.\n" ); render 0 ;} Pop posts from this blog
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